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//方式一:按条件查询
QueryWrapper<User> qw=new QueryWrapper<>();
qw.lt("age", 18);
List<User> userList = userDao.selectList(qw);
System.out.println(userList);
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//方式二:lambda格式按条件查询
QueryWrapper<User> qw = new QueryWrapper<User>();
qw.lambda().lt(User::getAge, 10);
List<User> userList = userDao.selectList(qw);
System.out.println(userList);
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//方式三:lambda格式按条件查询
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
lqw.lt(User::getAge, 10);
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
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//并且关系
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//并且关系:10到30岁之间
lqw.lt(User::getAge, 30).gt(User::getAge, 10);
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
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//或者关系
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//或者关系:小于10岁或者大于30岁
lqw.lt(User::getAge, 10).or().gt(User::getAge, 30);
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
如下搜索场景,在多条件查询中,有条件的值为空应该怎么解决?
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Integer minAge=10; //将来有用户传递进来,此处简化成直接定义变量了
Integer maxAge=null; //将来有用户传递进来,此处简化成直接定义变量了
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
if(minAge!=null){
lqw.gt(User::getAge, minAge);
}
if(maxAge!=null){
lqw.lt(User::getAge, maxAge);
}
List<User> userList = userDao.selectList(lqw);
userList.forEach(System.out::println);
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Integer minAge=10; //将来有用户传递进来,此处简化成直接定义变量了
Integer maxAge=null; //将来有用户传递进来,此处简化成直接定义变量了
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//参数1:如果表达式为true,那么查询才使用该条件
lqw.gt(minAge!=null,User::getAge, minAge);
lqw.lt(maxAge!=null,User::getAge, maxAge);
List<User> userList = userDao.selectList(lqw);
userList.forEach(System.out::println);
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Integer minAge=10; //将来有用户传递进来,此处简化成直接定义变量了
Integer maxAge=null; //将来有用户传递进来,此处简化成直接定义变量了
LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//参数1:如果表达式为true,那么查询才使用该条件
lqw.gt(minAge!=null,User::getAge, minAge)
.lt(maxAge!=null,User::getAge, maxAge);
List<User> userList = userDao.selectList(lqw);
userList.forEach(System.out::println);
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/*LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
lqw.select(User::getId, User::getName, User::getAge);*/
//或者
QueryWrapper<User> lqw = new QueryWrapper<User>();
lqw.select("id", "name", "age", "tel");
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
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QueryWrapper<User> lqw = new QueryWrapper<User>();
lqw.select("count(*) as count, tel");
lqw.groupBy("tel");
List<Map<String, Object>> userList = userDao.selectMaps(lqw);
System.out.println(userList);
多条件查询有哪些组合?
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LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//等同于=
lqw.eq(User::getName, "Jerry").eq(User::getPassword, "jerry");
User loginUser = userDao.selectOne(lqw);
System.out.println(loginUser);
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LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//范围查询 lt le gt ge eq between
lqw.between(User::getAge, 10, 30);
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
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LambdaQueryWrapper<User> lqw = new LambdaQueryWrapper<User>();
//模糊匹配 like
lqw.likeLeft(User::getName, "J");
List<User> userList = userDao.selectList(lqw);
System.out.println(userList);
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QueryWrapper<User> qw = new QueryWrapper<User>();
qw.select("gender","count(*) as nums");
qw.groupBy("gender");
List<Map<String, Object>> maps = userDao.selectMaps(qw);
System.out.println(maps);
题目:基于MyBatisPlus_Ex1模块,完成Top5功能的开发。
说明:
①:Top5指根据销售量排序(提示:对销售量进行降序排序)
②:Top5是仅获取前5条数据(提示:使用分页功能控制数据显示数量)
思考表的字段和实体类的属性不对应,查询会怎么样?
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"tbl_user") (
public class User {
/*
id为Long类型,因为数据库中id为bigint类型,
并且mybatis有自己的一套id生成方案,生成出来的id必须是Long类型
*/
private Long id;
private String name;
value = "pwd",select = false) (
private String password;
private Integer age;
private String tel;
exist = false) //表示online字段不参与CRUD操作 (
private Boolean online;
}